DescriptionFS E dia.png English: Equilateral triangle Deutsch: Gleichseitiges Dreieck Date 23 December 2021 Source Own work Author Hans G. Oberlack...
( 2 − 2 ) ⋅ s {\displaystyle r_{1}=(2-{\sqrt {2}})\cdot s\quad } See QH_dia 2) Radius of the additional circle r 2 = 2 − 2 2 ⋅ s {\displaystyle r_{2}={\frac...
{\displaystyle P_{1}={\frac {4+\pi }{2}}\cdot a\quad } , see details under FS QV dia.png 2) Perimeter of the circle: P 2 = 2 π r 2 = 2 π ⋅ ( 2 − 1 ) ⋅ a {\displaystyle...
|MD|=r_{3}} (7) | D F | = | E S 4 | = r 4 {\displaystyle |DF|=|ES_{4}|=r_{4}} , since F S 4 ¯ {\displaystyle {\overline {FS_{4}}}} is perpendicular to...
|MD|=r_{3}} (7) | D F | = | E S 4 | = r 4 {\displaystyle |DF|=|ES_{4}|=r_{4}} , since F S 4 ¯ {\displaystyle {\overline {FS_{4}}}} is perpendicular to...
radii are perpendicular to the tangent (6) | F S 2 | = | E S 2 | = r 2 {\displaystyle \quad |FS_{2}|=|ES_{2}|=r_{2}\quad } , since B A → {\displaystyle...
DescriptionFS E.png English: Equilateral triangle - Details: FS E dia.png Deutsch: Gleichseitiges Dreieck - Details: FS E dia.png Date 23 December 2021...
the circle within △ A F E {\displaystyle \triangle AFE} the following calculations have to be done: From the construction of FS_QH it is known that the...
{\displaystyle r_{1}} around point A {\displaystyle A} . From the developing of FS_CV we know that r 1 = 2 ⋅ r 0 {\displaystyle r_{1}={\sqrt {2}}\cdot r_{0}}...
C E J ] {\displaystyle [ACEJ]} of side length a 0 {\displaystyle a_{0}} . This means that the following equations hold (0.1) | A C | = | C E | = | E J...
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